Answer:
Option (1)
Step-by-step explanation:
[tex]\text{log}_4(x + 3)=\text{log}_2(2 + x)[/tex]
[tex]\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}[/tex]
[tex]\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}[/tex]
System of equations can be written as,
[tex]y_1=\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}[/tex]
[tex]y_2=\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}[/tex]
Therefore, system of equations given in Option (1) is the correct option.
