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01-03-2018
Chemistry

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The ksp of tin(ii) hydroxide, sn(oh)2, is 5.45 × 10-27. calculate the molar solubility of this compound.

Respuesta :

10-03-2018

Let x be mol/l of Sn(OH)2 that dissolve
Therefore, this will give x mol/l Sn2+ and 2x mol/l OH-
Ksp= (Sn2+)(OH-)^2
= (x)(2x)^2
= 4x^3
4x^3 = 5.45 × 10^-27
x = 1.11 × 10^-9
x = molar solubility = 1.11×10^-9 M

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