safax
safax
01-07-2016
Mathematics
contestada
verify the identity cot(x-pi/2)=-tanx
Respuesta :
NiedzielnyMatematyk
NiedzielnyMatematyk
03-07-2016
[tex]\cot(x-\frac{\pi}{2}) = \dfrac{\cos(x-\frac{\pi}{2})}{\sin(x-\frac{\pi}{2})} =\dfrac{\cos(-(\frac{\pi}{2}-x))}{\sin(-(\frac{\pi}{2}-x))} =\dfrac{\cos(\frac{\pi}{2}-x)}{-\sin(\frac{\pi}{2}-x)} =\\=-\dfrac{\sin x}{\cos x} = -\tan x[/tex]
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