lisapressley2001 lisapressley2001

01-01-2017
Mathematics

contestada

Solve using quadratic formula. 2x^2+6x+3=0

Respuesta :

01-01-2017

[tex]x = \frac{-b +/- \sqrt{b^{2} -4ac} }{2a} [/tex]

a = 2
b = 6
c = 3

[tex]x = \frac{-6 +/- \sqrt{6^{2} -4*2*3} }{2*2} [/tex]

[tex]x = 0.634[/tex] or [tex]x = -2.366[/tex]

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