(a) from the definition of capacitance c = q/δv, it follows that an uncharged capacitor has a capacitance of zero.

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01-02-2017
Physics

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(a) from the definition of capacitance c = q/δv, it follows that an uncharged capacitor has a capacitance of zero.

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All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

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andriansp andriansp · Answer 1 · 2017-02-06T23:53:43+01:00

andriansp andriansp

06-02-2017

That statement is true.
the capacitor is initially uncharged, but starts to charged when the switch is closed.
The potential difference across the resistor will steadily dropped as the potential difference across the capacitor increased.

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