johnnysHERE
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  • 02-02-2017
  • Mathematics
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Write the equation of a line that is perpendicular to the given line and that passes through the given point. y+2=1/3(x-5);(-4,3)

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Аноним Аноним
  • 02-02-2017
Here, equation of a line, y + 2 = 1/3 (x -5)
slope = 1/3

Slope of the line which is perpendicular would be -3   [ reciprocal & opposite ]

Now, y - y1 = m(x-x1)
y - 3 = -3(x - (-4))
y - 3 = -3x - 12
y = -3x - 9

In short, Your Answer would be y = -3x - 9

Hope this helps!
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