Seudónimo
Seudónimo
04-04-2017
Mathematics
contestada
Help with 2 questions?
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Аноним
Аноним
04-04-2017
1)Rewrite in standard form and use that to find the vertex, which would be (-2,15) so second option
2) second option
(both of the attachments are for the second problem, I was too lazy to write it out :P)
Answer Link
irspow
irspow
04-04-2017
vertex of -3x^2-12x+3
dy/dx=-6x-12, dy/dx=0 when:
-6x-12=0
-6x=12
x=-2
y(2)=-3x^2-12x+3=-12+24+3
y(2)=15
So the vertex is the point (-2, 15)
...
y=3x^2+12x-6
dy/dx=6x+12, dy/dx=0 when
6x+12=0
6x=-12
x=-2
y(-2)=3x^2+12x-6=12-24-6=-18
So it is the second one which has its vertex and absolute minimum at the point (-2, -18)
Answer Link
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