Respuesta :

MisterBrian

Answer:

y = 297

Step-by-step explanation:

We know,

[tex]\boxed{\sf LCM * HCF = Product \: of \: 2 \: numbers \: involved \: in \: HCF \: and \: LCM}[/tex]

Given, two numbers = x and y

LCM of them: 2079

HCF of them: 27

So, putting the values:

  • 2079 * 27 = x*y = xy ...(1)

Also given,

  • x/9 = 21 (Quotient)

Multiply both sides by 9:

  • x = 21*9

Putting the value of x in eqn (1):

  • 2079*27 = 21*9*y

Divide both sides by 21*9:

  • 2079*27/(21*9)= 21*9*y/21*9
  • 2079*3/21 = y (Cancel wherever required.)
  • 2079/7 = y ..(Interchange sides)
  • y = 297

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