Number of moles of HBr = 80.0 mL x(1L / 1000 mL) x (0.25 mol / L) = 0.02 mol Number of moles of KOH = 40.0 mL x (1 L / 1000 mL) x (0.5 mol / L) = 0.02 mol At this point all the acid is completely neutralized by base so; at the equivalence point pH of solution equal 7 (salt of strong acid and strong base KBr)
