Respuesta :

gmany
[tex]\cos\dfrac{3\pi}{4}=\cos\left(\pi-\dfrac{\pi}{4}\right)=-\cos\dfrac{\pi}{4}=-\dfrac{\sqrt2}{2}[/tex]

[tex]\sin\dfrac{3\pi}{4}=\sin\left(\pi-\dfrac{\pi}{4}\right)=\sin\dfrac{\pi}{4}=\dfrac{\sqrt2}{3}[/tex]

Look at the picture.

[tex]\dfrac{\pi}{2} < \dfrac{3\pi}{4} < \pi\\\\therefoere\\\\\cos\dfrac{3\pi}{4} < 0\ and\ \sin\dfrac{3\pi}{4} > 0[/tex]



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